Sunday, October 28, 2012

Immunoglobulin (Ig)


DEFINITION 
Immunoglobulin (Ig) 
Immunoglobulins are glycoprotein molecules that function as antibodies and are produced by plasma cells in response to an immunogen. The immunoglobulins derive their name from the finding that they migrate in the region of globulins when antibody-containing serum is placed in an electrical field.









Figure- 1-showing the  Electrophoretic separation of plasma proteins 
BASIC STRUCTURE OF IMMUNOGLOBULINS
Although different immunoglobulins differ structurally but they all are built from the same basic units.(Figure-2)
A. Heavy and Light Chains 
All immunoglobulins have a four chain structure as their basic unit. They are composed of two identical light chains (23kD) and two identical heavy chains (50-70kD)
B. Disulfide bonds
1. Inter-chain disulfide bonds - The heavy and light chains and the two heavy chains are held together by inter-chain disulfide bonds and by non-covalent interactions .The number of inter-chain disulfide bonds varies among different immunoglobulin molecules.
2. Intra-chain disulfide binds - Within each of the polypeptide chains there are also intra-chain disulfide bonds.
C. Variable (V) and Constant (C) Regions 
Both the heavy and light chain can be divided into two regions based on variability in the amino acid sequences. These are the
1. Light Chain – VL (110 amino acids) and CL (110 amino acids)
2. Heavy Chain – VH (110 amino acids) and CH (330-440 amino acids)
D. Hinge Region 
This is the region at which the arms of the antibody molecule form a Y. It is called the hinge region because there is some flexibility in the molecule at this point.
E. Domains 
Three dimensional images of the immunoglobulin molecule show that it is not a straight molecule rather, it is folded into globular regions each of which contains an intra-chain disulfide bond (figure-2). These regions are called domains.
1. Light Chain Domains – VL and CL
2. Heavy Chain Domains – VH, CH1,CH2CH3 (or CH4)
F. Oligosaccharides 
Carbohydrates are attached to the CH2 domain in most immunoglobulins. However, in some cases carbohydrates may also be attached at other locations.















Figure-2- showing the general structure of Immunoglobulin
GENERAL FUNCTIONS OF IMMUNOGLOBULINS
A. Antigen binding 
Immunoglobulins bind specifically to one or a few closely related antigens. Each immunoglobulin actually binds to a specific antigenic determinant. Antigen binding by antibodies is the primary function of antibodies and can result in protection of the host.  The valency of antibody refers to the number of antigenic determinants that an individual antibody molecule can bind. The valency of all antibodies is at least two and in some instances more.














Figure-3- Showing the general structure of Immunoglobulin and  structure of antigen binding cleft. Antigenic determinants are present on the surface of  antigen while the antigen binding sites are present in the antigen binding cleft made by both light chain and heavy chain
B. Effector Functions 
Frequently the binding of an antibody to an antigen has no direct biological effect. Rather, the significant biological effects are a consequence of secondary “effector functions” of antibodies. The immunoglobulins mediate a variety of these effector functions. Not every immunoglobulin will mediate all effector functions. Such effector functions include:
1. Fixation of complement - This results in lysis of cells and release of biologically active molecules
2. Binding to various cell types – Phagocytic cells, lymphocytes, platelets, mast cells, and basophils have receptors that bind immunoglobulins. This binding can activate the cells to perform some function.














Figure-4 showing the receptors present on the surface of macrophages to bind the antigen antibody complex

Some immunoglobulins also bind to receptors on placental trophoblasts, which results in transfer of the immunoglobulin across the placenta. As a result, the transferred maternal antibodies provide immunity to the fetus and newborn.

















Figure- 5 showing the functions of different regions of the immunoglobulins

IMMUNOGLOBULIN FRAGMENTS: STRUCTURE/FUNCTION RELATIONSHIPS
Immunoglobulin fragments produced by proteolytic digestion -
A.  Fab 
Digestion with papain breaks the immunoglobulin molecule in the hinge region before the H-H inter-chain disulfide bond Figure 6. This results in the formation of two identical fragments that contain the light chain and the VH and CH1 domains of the heavy chain.


















Figure-6 showing the  site of action of Papain (a proteolytic enzyme).  Fab and Fc are the two fragments obtained by proteolytic cleavage.
Antigen binding - These fragments are  called the Fab fragments because they contained the antigen binding sites of the antibody. Each Fab fragment is monovalent whereas the original molecule was divalent. The combining site of the antibody is created by both VH and VL
B. Fc 
Digestion with papain also produces a fragment that contains the remainder of the two heavy chains each containing a CH2 and CH3 domain. This fragment was called Fc because it was easily crystallized.
Effector functions - The effector functions of immunoglobulins are mediated by this part of the molecule. Different functions are mediated by the different domains in this fragment (figure 5). 

















Figure-7- showing the site of action of Pepsin on Immunoglobulin.
C. F(ab’)2 
Treatment of immunoglobulins with pepsin results in cleavage of the heavy chain after the H-H inter-chain disulfide bonds resulting in a fragment that contains both antigen binding sites (figure 7). This fragment is called F(ab’)2because it is divalent. The Fc region of the molecule is digested into small peptides by pepsin. The F(ab’)2binds antigen but it does not mediate the effector functions of antibodies.
HUMAN IMMUNOGLOBULIN CLASSES, SUBCLASSES, TYPES AND SUBTYPES
A. Immunoglobulin classes 
The immunoglobulins can be divided into five different classes, based on differences in the amino acid sequences in the constant region of the heavy chains. All immunoglobulins within a given class will have very similar heavy chain constant regions. 
1. IgG – Gamma  heavy chains
2. IgM – Mu  heavy chains
3. IgA – Alpha heavy chains
4. IgD – Delta  heavy chains
5. IgE – Epsilon  heavy chains
Immunoglobulin Subclasses 
The classes of immunoglobulins can de divided into subclasses based on small differences in the amino acid sequences in the constant region of the heavy chains. All immunoglobulins within a subclass will have very similar heavy chain constant region amino acid sequences. 
1. IgG Subclasses
a) IgG1 – Gamma 1  heavy chains
b) IgG2 – Gamma 2  heavy chains
c) IgG3 – Gamma 3  heavy chains
d) IgG4 – Gamma 4  heavy chains
2. IgA Subclasses
a) IgA1 – Alpha 1  heavy chains
b) IgA2 – Alpha 2  heavy chains
 Immunoglobulin Types 
Immunoglobulins can also be classified by the type of light chain that they have. Light chain types are based on differences in the amino acid sequence in the constant region of the light chain. 
1. Kappa light chains 
2. Lambda light chains 
 STRUCTURE AND SOME PROPERTIES OF IG CLASSES AND SUBCLASSES
A.  IgG
1. Structure
 All IgG’s are monomers (7S immunoglobulin). The subclasses differ in the number of disulfide bonds and length of the hinge region.
2. Properties
IgG is the most versatile immunoglobulin because it is capable of carrying out all of the functions of immunoglobulin molecules.
a) IgG is the major Ig in serum – 75% of serum Ig is IgG
b) IgG is the major Ig in extra vascular spaces
c) Placental transfer – IgG is the only class of Ig that crosses the placenta. Transfer is mediated by a receptor on placental cells for the Fc region of IgG. Not all subclasses cross equally well; IgG2 does not cross well.
d) Fixes complement – Not all subclasses fix equally well; IgG4 does not fix complement
e) Binding to cells – Macrophages, monocytes and neutrophils and some lymphocytes have Fc receptors for the Fc region of IgG.  A consequence of binding to the Fc receptors on such cells  is that the cells can now internalize the antigen better. The antibody prepares the antigen for killing by the phagocytic cells. The term opsonin is used to describe substances that enhance phagocytosis. (Coating of the surface of pathogen by antibody is called opsonization).IgG is a good opsonin. Binding of IgG to Fc receptors on other types of cells results in the activation of other functions.















Figure-8- showing the structure of Ig G 
IgM
1. Structure
 IgM normally exists as a pentamer (19S immunoglobulin) but it can also exist as a monomer. In the pentameric form all heavy chains are identical and all light chains are identical. Thus, the valence is theoretically 10. IgM has an extra domain on the mu chain (CH4) and it has another protein covalently bound via a S-S bond called the J chain. This chain functions in polymerization of the molecule into a pentamer.
2. Properties
a) IgM is the third most common serum Ig.
b) IgM is the first Ig to be made by the fetus and the first Ig to be made by a virgin B cells when it is stimulated by antigen.
c) As a consequence of its pentameric structure, IgM is a good complement fixing Ig. Thus, IgM antibodies are very efficient in leading to the lysis of microorganisms.
d) As a consequence of its structure, IgM is also a good agglutinating Ig . Thus, IgM antibodies are very good in clumping microorganisms for eventual elimination from the body.
e) IgM binds to some cells via Fc receptors.
f) B cell surface Ig 
Surface IgM exists as a monomer and lacks J chain but it has an extra 20 amino acids at the C-terminus to anchor it into the membrane . Cell surface IgM functions as a receptor for antigen on B cells.















 Figure-9- showing the structure of Ig M 
IgA
1. Structure
Serum IgA is a monomer but IgA found in secretions is a dimer as presented in Figure 10. When IgA exits as a dimer, a J chain is associated with it.
When IgA is found in secretions is also has another protein associated with it called the secretory piece or T piece; sIgA is sometimes referred to as 11S immunoglobulin. Unlike the remainder of the IgA which is made in the plasma cell, the secretory piece is made in epithelial cells and is added to the IgA as it passes into the secretions . The secretory piece helps IgA to be transported across mucosa and also protects it from degradation in the secretions.


















Figure-10- showing the structure of Ig A 
2. Properties
a) IgA is the 2nd most common serum Ig.
b) IgA is the major class of Ig in secretions – tears, saliva, colostrum, mucus. Since it is found in secretions secretory IgA is important in local (mucosal) immunity.
c) Normally IgA does not fix complement, unless aggregated.
d) IgA can binding to some cells – PMN’s and some lymphocytes.

IgD
1. Structure
 IgD exists only as a monomer.
2. Properties
a) IgD is found in low levels in serum; its role in serum  is uncertain.
b) IgD is primarily found on B cell surfaces where it functions as a receptor for antigen.
 c) IgD does not bind complement.











Figure-11- showing the structure of Ig D 
E. IgE
1. Structure

IgE exists as a monomer and has an extra domain in the constant region.
2. Properties
a) IgE is the least common serum Ig since it binds very tightly to Fc receptors on basophils and mast cells even before interacting with antigen.
b) Involved in allergic reactions – As a consequence of its binding to basophils and mast cells, IgE is involved in allergic reactions. Binding of the allergen to the IgE on the cells results in the release of various pharmacological mediators that result in allergic symptoms.
c) IgE also plays a role in parasitic helminth diseases. Since serum IgE levels rise in parasitic diseases, measuring IgE levels is helpful in diagnosing parasitic infections. Eosinophils have Fc receptors for IgE and binding of eosinophils to IgE-coated helminths results in killing of the parasite.
d) IgE does not fix complement.












Figure-12- showing the structure of Ig E



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Chemistry of lipids


Q.1- Endogenously synthesized triacylglycerols are transported from liver to extra hepatic tissues by which of the followinglipoproteins?
a) Chylomicrons
b) VLDL
c) LDL
d) HDL     
Q.2- All of the followings have 18 carbon atoms except –
a) Linoleic acid
b) Palmitic acid
c) Linolenic acid
d) Stearic acid        
Q.3- Sphingosine is not present in-
a) Cerebrosides
b) Gangliosides
c) sphigomyelin
d) Plasmalogen                         
Q.4- Triacylglycerols are-
a) Energy rich compounds
b) Nonpolar in nature
c) Can be stored in unlimited amounts
d) All of the above           
Q.5- All are essential fatty acids except-              
a)Linoleic,
b) Linolenic
c) Arachidonic acid
d) Stearic acid        
Q.6- The deficiency of Lung surfactant, Dipalmitoyllecithin (DPL) causes, Respiratory Distress Syndrome. DPL is a –
a) Cerebroside
b) Ganglioside
c) Phospholipid
d) Lipoprotein
Q.7- Choose the correct statement
a) The melting point of a fatty acid increases with the increasing degree of unsaturation in the hydrophobic chain
b) Most of the naturally fatty acids have trans double bonds
c) Arachidonic acid is a relatively nonessential fatty acid
d) The membrane lipids are rich in saturated fatty acids.
Q.8- Which out of the following fatty acids is a precursor of series -1 Eicosanoids?
a) Linoleic acid
b) Arachidonic acid
c) Eicosapentaenoic acid
d) Linolenic acid
Q.9- What is the cause of hyper acidity on long-term usage of Aspirin?
a) Inhibition of cyclo oxygenase
b) Increased synthesis of PGs
c) Inhibition of Phospholipase A2
d) All of the above
Q.10- Which nitrogenous base out of the followings is present in lecithin —?
a)Choline
b) Adenine
c) Ethanolamine
d) Any of the above
Q.11- Cholesterol is a precursor of all except-
a)Bile salts,
b)Bilirubin
c) Steroids
d) vitamin D                             
Q.12- Glycerol is used for the synthesis of all except-
a) Glucose.,
b) Phospholipids,
c) Glycolipids,
d) Triacylglycerol             
Q.13- Which out of the followings is a fatty acid with 16 carbon atoms and one double bond?
a) Palmitoleic acid
b) Oleic acid
c) Erucic acid
d) Elaidic acid
Q.14-Which out of the followings is an ώ 3 fatty acid?
a) α Linolenic acid
b) Linoleic acid
c) Palmitic acid
d) Arachidonic acid
Q.15- Fats on keeping fora long time under go spontaneous hydrolysis, what is this process called?
a) Saponification
b) Hydrolytic Rancidity
c) Decomposition
d) All of the above
Q.16-  Which out of the following enzymes is deficient  in Gaucher’s disease?    
a) Beta Glucosidase
b) Beta Galactosidase
c) Hexosaminidase A
d) Neuraminidase
Q.17- Prostcyclins are synthesized in- ———?      
a) Platelets   
b) Endothelial cells
c) Gastric mucosa
d) Basophils
Q.18- Cyclo-oxygenase is inhibited by all except——–? 
a) Aspirin
b) Indomethacin
c) Brufen
d) Zileuton
Q.19- The normal level of serum Total cholesterol is———–?
a) 150-220 mg/dl
b) 100-200 mg/dl
c) 1.5-2.5g/dl
d) 20-40 mg/dl
Q.20- Choose out of the followings, a fatty acid with 20 carbon atoms and five double bonds-
a) Timnodonic acid
b) Arachidonic acid
c) Clupanodonic acid
d) Nervonic acid
Q.21- Which type of lipid is a receptor for cholera toxin in the intestine?
a) GM2 Ganglioside
b) GM1Ganglioside
c) Sphingomyelin
d) Galactocerebroside
Q.22- The significance of estimating L: S ratio of amniotic fluid in a pregnant female lies in evaluating-
a) Fetal heart rate                                         
b) Fetal lung maturity
c) Fetal head size
d) Expected date of delivery
Q.23- Iodine number is a measure of-
a) Degree of unsaturation of a fat
b) Degree of rancidity of a fat
c) Measure of volatile fatty acids in a fat
d) Measure of number of –OH groups in a fat
Q.24-Which phospholipid out of the following is antigenic in nature -?     
a) Cardiolipin
b) Lecithin
c) Plasmalogen
d) Cephalin
Q.25- Which out of the followings is not a derived lipid?
a) Ketone body
b) PGE2  
c) Diacylglycerol,
d) Galactosyl ceramide              
Q.26- What are the components of a ceramide?                      
a) Sphingosine+ fatty acid
b) Glycerol+Fatty acids+Phosphoric acid
c) Glycerol+Fatty acids+Phosphoric acid+Nitoregenous base
d) Sphingosine+ fatty acids+Phosphoric acid
Q.27- Choose the incorrect statement-
a) The chemical name of Arachidonic acid is Eicosa penta enoicacid       
b) Cyclo-oxygenase and peroxidase are the components of PG-Hsynthase complex
c) Oleic acid is represented by 18;1,∆9
d) NSAIDs act by inhibiting Phospholipase A2 enzyme.
 Answers-
1-(b)- VLDL
2-(b)- Palmitic acid
3-(d)- Plasmalogen
4-(d) All of the above
5-(d) Stearic acid
6-(c) Phospholipid
7-(c) Arachidonic acid
8-(a) Linoleic acid
9-(a)- Inhibition of cyclo-oxygenase enzyme
10-(a) Choline
11-(b) Bilirubin
12-(c) Glycolipids
13-(a) –Palmitoleic acid
14-(a)-α- Linolenic acid
15-(b)-Hydrolytic Rancidity
16-(a) Beta Glucosidase
17-(b)-Endothelial cells
18-(d)-Zileuton
19-(a) 150-220 mg/dL
20-(a) Timnodonic acid
21-(b) GM1- Ganglioside
22-(b) Fetal lung maturity
23-(a)- Degree of unsaturation
24-(a)- Cardiolipin
25-(a)- Galactosyl Ceramide
26-(a)- Sphingosine+Fatty acid
27-(d) NSAIDs act by inhibiting PhospholipaseA2 enzyme


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Multiple Choice Questions- Chemistry of Carbohydrates


Q.1-Which of the followings is a simple sugar or monosaccharide?
a) Galactose
b) Lactose
c) Maltose
d) Sucrose
Q.2- What is the molecular formula for Glucose?
a) CH3OH
b) C6H1206
c) C12H22O11
d) C6H12O5
Q.3- Maltose is composed of which two sugars?
a) Glucose and Glucose
b) Glucose and Galactose
c) Glucose and Fructose
d) Fructose and Galactose
Q.4- In which form is Glucose stored in animals?
a) Starch
b) Glycogen
c) Dextrins
d) Cellulose
Q.5-All are glucosans (polymers of glucose) except-
a) Glycogen
b) Inulin
c) Starch
d) Cellulose
Q.6- Choose the Aldose sugar out of the followings-
a) Sucrose
b) Ribulose
c) Fructose
d) Ribose
Q.7- Choose the keto triose-
a) Glyceraldehyde
b) Erythrose
c) Dihydroxyacetone
d) Arabinose
Q.8- A pentose sugar present in the heart muscle is-
a) Xylose
b) Lyxose
c) Xylulose
d) Aldose
Q.9- α-D Glucose and β- D glucose are-
a) Epimers
b) Keto- Aldose Isomers
c) Anomers
d) Optical isomers
Q.10- All tests are negative for sucrose except-
a) Benedict
b) Seliwanoff
c) Barfoed
d) Osazone
Q.11- Glucose can have ————- isomers due to the presence of 4 asymmetric carbon atoms-
a) 4
b) 12
c) 8
d) 16
Q.12- Galactose and Glucose are-
a) Epimers
b) Isomers
c) Anomers
d)Ketose- Aldose isomers
Q.13- The compounds having same structural formula but differing in configuration around one carbon atom are called-
a) Optical isomers
b) Stereo isomers
c) Anomers
d) Epimers
Q.14- What does the following equation represent?   
 α-D Glucose +112ο+52.5ο  +19οβ- D glucose
 a) Stereo isomerism
b) Mutarotation
c) Optical isomerism
d) Epimerization
Q.15- The carbohydrate of blood group substance is-
a) Fucose
b) Xylose
c) Lyxose
d) Fructose
Q.16- Dulcitol is a -
a) Sugar acid
b) Amino sugar
c) Deoxysugars
d) Sugar alcohol
Q.17- Which of the following is a non reducing sugar-
a) Arabinose
b) Erythrose
c) Trehalose
d) Ribulose
Q.18- A Polysaccharide formed by β14 Glycosidic linkages is-
a) Starch
b) Dextrin
c) Glycogen
d) Cellulose
Q.19-Invert sugar is-
a) Starch
b) Glucose
c) Fructose
d) Hydrolytic product of Sucrose
Q.20- The Polysaccharide found in the exoskeleton of insects is-
a) Hyaluronic acid
b) Cellulose
c) Chitin
d) Chondrosamine
Q,21- Which of the following is a polymer of fructose?
a) Inulin
b)Dextrin
c) Cellulose
d) Glycogen
Q.22- A disaccharide produced on hydrolysis of starch is called-
a) Sucrose
b) Lactose
c) Maltose
d) Trehalose
Q.23-The typical cyclical structure of Glucose is α and β D-
a) Glucopyranose
b) Glucoside
c) Glucofuranose
d) Glucosamine
Q.24- Which test can be undertaken to differentiate between Glucose and Fructose?
a) Benedict
b) Molisch
c) Seliwanoff
d) Osazone
Q.25- Which of the following molecules is a carbohydrate?
a) C3 H7O2N
b) C13H26O2
c) C6H12O6
d) C20H40O2
Q.26- Which of the following monosaccharides is not an aldose?
a) Ribose
b) Fructose
c) Glucose
d) Glyceraldehyde
Q.27-Which of following is an anomeric pair?
a) D-glucose and L-glucose
b) α-D-glucose and β-D-glucose
c) D-glucose and D-fructose
d) α-D-glucose and β-L-glucose
Q.28- Which of the following monosaccharides is not a carboxylic acid?
a) Glucuronate
b) Gluconate
c) Glucose
d) Muramic acid
Q.29- From the abbreviated name of the compound Gal (β 1 →4) Glc, we know that:
a) The glucose residue is the β anomer.
b) The galactose residue is at the non reducing end.
c) C-4 of glucose is joined toC-1 of galactose by a glycosidic bond.
d) The compound is in its furanose form
Q.30- The compound that consists of ribose linked by an N-glycosidic bond to N-9 of adenine is:
a) A purine nucleotide.
b) A pyrimidine nucleotide.
c) Adenosine.
d) AMP

Key to answers
1)-a,      2)-b,      3)-a,      4)-b,      5)-b,      6)-d,     7)-c,      8)-b,     9)-c,      10)-b,   11)-d,    12)-a,    13)-d,
14)-b,    15)-a,    16)-d,   17)-c,    18)-d,   19)-d,   20)-c,   21)-a,    22)-c,   23)-a,   24)-c,   25)-c,   26)-b,  
27)-b,   28)-c,   29)-c,   30)-c




------------------------------------------ Best Wishes: Dr.Ehab Aboueladab, Tel:01007834123 Email:ehab10f@gmail.com,ehababoueladab@yahoo.com ------------------------------------------